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Friday, 20 September 2013

Integrals

page -299
Question 1:sin 2x

Answer:

The anti derivative of sin 2x is a function of x whose derivative is sin 2x.
It is known that,
Therefore, the anti derivative of
Question 2:

Cos 3x

Answer:

The anti derivative of cos 3x is a function of x whose derivative is cos 3x.
It is known that,
Therefore, the anti derivative of .
Question 2:

Cos 3x

Answer:

The anti derivative of cos 3x is a function of x whose derivative is cos 3x.
It is known that,
Therefore, the anti derivative of .

Question 3:

e2x

Answer:

The anti derivative of e2is the function of x whose derivative is e2x.
It is known that,
Therefore, the anti derivative of .

Question 4:


Answer:

The anti derivative of is the function of whose derivative is .
It is known that,
Therefore, the anti derivative of .

Question 5:


Answer:

The anti derivative of  is the function of x whose derivative is .
It is known that,
Therefore, the anti derivative of  is .

Question 6:


Answer:


Question 7:


Answer:



Question 8:


Answer:


Question 9:


Answer:


Question 10:


Answer:

Question 11:


Answer:


Question 12:


Answer:


Question 13:


Answer:

On dividing, we obtain

Question 14:


Answer:


Question 15:


Answer:


Question 16:


Answer:


Question 17:


Answer:


Question 18:


Answer:


Question 19:


Answer:


Question 20:


Answer:


Question 21:

The anti derivative of equals
(A) (B) 
(C) (D)

Answer:

Hence, the correct answer is C.

Question 22:

If such that f(2) = 0, then f(x) is
(A) (B) 
(C) (D)

Answer:

It is given that,
∴Anti derivative of 
Also,
Hence, the correct answer is A.

Page-304
Question 1:


Answer:

Let t
∴2x dx = dt

Question 2:


Answer:

Let log |x| = t
∴ 

Question 3:


Answer:

Let 1 + log t
∴ 

Question 4:

sin x ⋅ sin (cos x)

Answer:

sin x ⋅ sin (cos x)
Let cos x = t
∴ −sin x dx = dt

Question 5:


Answer:

Let 
∴ 2adx = dt

Question 6:


Answer:

Let ax + b = t
⇒ adx = dt

Question 7:


Answer:

Let 
∴ dx = dt

Question 8:


Answer:

Let 1 + 2x2 = t
∴ 4xdx = dt

Question 9:


Answer:

Let 
∴ (2x + 1)dx = dt

Question 10:


Answer:

Let 

Question 11:


Answer:

Let 
∴ dx = dt

Question 12:


Answer:

Let 
∴ 

Question 13:


Answer:

Let 
∴ 9x2 dx = dt

Question 14:


Answer:

Let log x = t
∴ 

Question 15:


Answer:

Let 
∴ −8x dx = dt
Question 16:


Answer:

Let 
∴ 2dx = dt
Question 17:


Answer:

Let 
∴ 2xdx = dt
Pg 305

Question 18:

Answer:
Let 
∴ 

Question 19:

Answer:
Dividing numerator and denominator by ex, we obtain
Let 
∴ 

Question 20:

Answer:
Let 
∴ 

Question 21:

Answer:
Let 2x − 3 = t
∴ 2dx = dt

Question 22:

Answer:
Let 7 − 4x = t
∴ −4dx = dt

Question 23:

Answer:
Let 
∴ 

Question 24:

Answer:
Let 
∴ 

Question 25:

Answer:
Let 
∴ 

Question 26:

Answer:
Let 
∴ 

Question 27:

Answer:
Let sin 2x = t
∴ 

Question 28:

Answer:
Let 
∴ cos x dx = dt

Question 29:
cot x log sin x

Answer:
Let log sin x = t

Question 30:

Answer:
Let 1 + cos x = t
∴ −sin x dx = dt

Question 31:

Answer:
Let 1 + cos x = t
∴ −sin x dx = dt
Question 32:

Answer:
Let sin x + cos x = t ⇒ (cos x − sin xdx = dt

Question 33:

Answer:
Put cos x − sin x = t ⇒ (−sin x − cos xdx = dt

Question 34:

Answer:

Question 35:

Answer:
Let 1 + log x = t
∴ 

Question 36:

Answer:
Let 
∴ 

Question 37:

Answer:
Let x4 = t
∴ 4x3 dx = dt
Let 
From (1), we obtain

Question 38:
equals

Answer:
Let 
∴ 
Hence, the correct answer is D.

Question 39:
equals
A.
B.
C.
D.

Answer:
Hence, the correct answer is B.

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