page -299
Question 1:sin 2x
Answer:
The anti derivative of sin 2x is a function of x whose derivative is sin 2x.
It is known that,
Therefore, the anti derivative of
Question 2:
Cos 3x
Answer:
The anti derivative of cos 3x is a function of x whose derivative is cos 3x.
It is known that,
Therefore, the anti derivative of
.
Question 2:
Cos 3x
Answer:
The anti derivative of cos 3x is a function of x whose derivative is cos 3x.
It is known that,
Therefore, the anti derivative of
.
Question 3:
e2x
Answer:
The anti derivative of e2x is the function of x whose derivative is e2x.
It is known that,
Therefore, the anti derivative of
.
Question 4:
Answer:
The anti derivative of
is the function of x whose derivative is
.
It is known that,
Therefore, the anti derivative of
.
Question 5:
Answer:
The anti derivative of
is the function of x whose derivative is
.
It is known that,
Therefore, the anti derivative of
is
.
Question 6:
Answer:
Question 7:
Answer:
Question 8:
Answer:
Question 9:
Answer:
Question 10:
Answer:
Question 11:
Answer:
Question 12:
Answer:
Question 13:
Answer:
On dividing, we obtain
Question 14:
Answer:
Question 15:
Answer:
Question 16:
Answer:
Question 17:
Answer:
Question 18:
Answer:
Question 19:
Answer:
Question 20:
Answer:
Question 21:
The anti derivative of
equals
(A)
(B) 
(C)
(D) 
Answer:
Hence, the correct answer is C.
Question 22:
If
such that f(2) = 0, then f(x) is
(A)
(B) 
(C)
(D) 
Answer:
It is given that,
∴Anti derivative of 
∴
Also,
Hence, the correct answer is A.
Page-304
Question 1:
Answer:
Let
= t
∴2x dx = dt
Question 2:
Answer:
Let log |x| = t
∴ 
Question 3:
Answer:
Let 1 + log x = t
∴ 
Question 4:
sin x ⋅ sin (cos x)
Answer:
sin x ⋅ sin (cos x)
Let cos x = t
∴ −sin x dx = dt
Question 5:
Answer:
Let 
∴ 2adx = dt
Question 6:
Answer:
Let ax + b = t
⇒ adx = dt
Question 7:
Answer:
Let 
∴ dx = dt
Question 8:
Answer:
Let 1 + 2x2 = t
∴ 4xdx = dt
Question 9:
Answer:
Let 
∴ (2x + 1)dx = dt
Question 10:
Answer:
Let 
∴
Question 11:
Answer:
Let 
∴ dx = dt
Question 12:
Answer:
Let 
∴ 
Question 13:
Answer:
Let 
∴ 9x2 dx = dt
Question 14:
Answer:
Let log x = t
∴ 
Question 15:
Answer:
Let 
∴ −8x dx = dt
Question 16:
Answer:
Let 
∴ 2dx = dt
Question 17:
Answer:
Let 
∴ 2xdx = dt
Pg 305

equals
equals
Question 18:
Answer:
Let 
∴ 
Question 19:
Answer:
Dividing numerator and denominator by ex, we obtain
Let 
∴ 
Question 20:
Answer:
Let 
∴ 
Question 21:
Answer:
Let 2x − 3 = t
∴ 2dx = dt
Question 22:
Answer:
Let 7 − 4x = t
∴ −4dx = dt
Question 23:
Answer:
Let 
∴ 
Question 24:
Answer:
Let 
∴ 
Question 25:
Answer:
Let 
∴ 
Question 26:
Answer:
Let 
∴ 
Question 27:
Answer:
Let sin 2x = t
∴ 
Question 28:
Answer:
Let 
∴ cos x dx = dt
Question 29:
cot x log sin x
Answer:
Let log sin x = t
Question 30:
Answer:
Let 1 + cos x = t
∴ −sin x dx = dt
Question 31:
Answer:
Let 1 + cos x = t
∴ −sin x dx = dt
Question 32:
Answer:
Let sin x + cos x = t ⇒ (cos x − sin x) dx = dt
Question 33:
Answer:
Put cos x − sin x = t ⇒ (−sin x − cos x) dx = dt
Question 34:
Answer:
Question 35:
Answer:
Let 1 + log x = t
∴ 
Question 36:
Answer:
Let 
∴ 
Question 37:
Answer:
Let x4 = t
∴ 4x3 dx = dt
Let 
∴
From (1), we obtain
Question 38:
Answer:
Let 
∴ 
Hence, the correct answer is D.
Question 39:
A. 
B. 
C. 
D. 
Answer:
Hence, the correct answer is B.
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